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sin2X (¦Ø¦Ö+ji /4) = sin (2 ¦Ø ¦Ö+ji /2) = cos (2 ¦Ø ¦Ö)S23 = sin2 X (¦Ø¦Ö + ji /2) = sin (2¦Ö+ ji ) = -sin (2 ¦Ø ¦Ö)S24 = sin2 X (¦Ø ¦Ö+3 Ji /4) = -cos (2 ¦Ø ¦Ö)(4)ΪÁË×¼±¸µÚ¶þ¼¶ÐźÅ761a_764aµÄƵÂʵĽøÒ»²½±¶Ôö£¬¿ÉÒÔ½«µÚ¶þ¼¶ÐźŠ761a-764aµÄ×éºÏÁ¬½Óµ½°üº¬²î·Öµç·771£¬772£¬773ºÍ774µÄµÚÒ»²î·Ö¼¶770£¬ÒÔÀûÓõÈʽ (5)ËùʾµÄÈý½Ç¼¸ºÎµÈʽ»ñµÃÏàλÏà²î45¶ÈµÄÐźÅ¡£²î·Öµç·771-774¿ÉÒÔÊÇÍêÈ«²î·Öµç·¡£ÎªÁ˼ò»¯Æð¼û£¬ÔÚͼ7AÖÐÊ¡ÂÔÁË·´À¡µç×èºÍ²Î¿¼µçѹ¡£sin(2cox+ji/4) = I/ V 2 (sin (2 ¦Ø x+cos (2 ¦Ø ¦Ö))cos (2 ¦Ø ¦Ö+ ji /4) = 1/( V 2 (cos (2 ¦Ø ¦Ö) -sin (2 ¦Ø ¦Ö)) (5)ÀýÈ磬Õâ¿ÉÒÔͨ¹ýÈçÏÂÀ´ÊµÏÖ¼ÆËãµÚÈý¼¶ÐźÅ7713-77 µÄ×éºÏµÄ²î£¬Èçͼ7¦¡Ëùʾ£¬²¢½«Ëù¼ÆËã³öµÄ²îÓë³£ÊýÏà³Ë£¬ÒÔ»ñµÃ¶à¸öµÚÈý¼¶ÐźÅ7713-77 ºÍ771b-774b¡£ÊýѧģÐÍʾÓÚµÈʽ(6)¡£1/2X (S21-S23) = sin(2 ¦Ø¦Ö)1/( v 2) x (s22-s23) = sin (2 ¦Ø x+ ji /4)1/2 X (S22-S24) = cos (2 ¦Ø ¦Ö) 1/( V 2) X (S22-S21) = cos (2 ¦Ø ¦Ö+ ji /4) (6)ÔÚʵʩ·½Ê½ÖÐʹÓõij£Êý·Ö±ðÊÇ{1/2£¬1/ V 2,1/2,1/ V 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